Physics 220 Laboratory: Magnetic Forces and
Currents
Introduction
In this laboratory we will be
testing the validity of the Lorentz force law which tells us how electric
charges are affected by electric and magnetic fields:
F = q
[ E + v × B ]
. (1)
For the case when there is no
net electric field present we just have that
FB
= q v × B .
(2)
|FB|
= q |v| |B| sin(θ) ,
(3)
with the direction of the force
determined via the right-hand rule.
In terms of current in a wire,
I, we can rewrite the magnetic force using q v = I
L where L is a length of wire in the magnetic field and the vector, L,
points in the direction of the current along the wire. We therefore find that
the magnetic force on a current-carrying wire is
FB
= I L × B
, (4)
and also that
|FB|
= I L |B| sin(θ) ,
(5)
with the direction of the force
determined via the right-hand rule.
Apparatus
The apparatus provided can
measure the force on a length of a current-carrying wire in a magnetic field set
up by two magnets. The power supply provides a current that can be varied from
–4 amperes to +4 amperes by changing the current dial on the power supply and by
reversing the red and black wires to the power supply.
The magnetic field is provided
by two rare earth magnets and the North and South poles of the magnetic
configuration is lined up with the N (at 0 degrees and the star: *) and S (at
180 degrees) on the paper dial beneath the cup. This configuration allows you
to change the orientation of the magnetic field with respect to the
current-carrying wire. The net magnetic force from Eq. (5) is due to the
horizontal length of wire, L, in the magnetic field.
This force is measured via
Newton’s third law as the force that the current-carrying wire pushes/pulls back
on the magnet-and-cup system. This force is measured by the digital balance as
the new mass of the magnet and cup, M'. Therefore, the difference
between the new mass and true mass is the effective mass due to the magnetic
force:
me
= M' – M
and the force due to the
current-carrying wire is then just FB = meg
which can be either positive or negative (up or down). This force is in newtons
when the mass is provided in kg.
WARNING: Do not leave
the magnet and cup configuration on the digital balance when you are not
performing the experiment. The digital balance is extremely sensitive and
leaving the mass on the balance longer than you need to, or in between
experiments, can affect the digital balances and therefore your experimental
results.
A. Determine |B| and linearity of |FB|
with the current, I.
- Verify with the compass
provided that in the horizontal plane of the magnets, the North pole of the
magnetic configuration is aligned with the star and 0 degrees on the paper
dial beneath the cup.
- There are three lengths of
wire in the magnetic field of the magnet: two vertical and one horizontal.
Why are we only considering the length, L, of the horizontal
length of wire? Use Eq. (4) to justify your result.
- Determine from Newton’s
third law which direction of the current makes me > 0 and
me < 0.
- Measure with a Vernier
caliper the horizontal length of wire that will be in the magnetic field of
the magnet configuration.
- Place the magnet and cup
system on the digital balance and orient the digital balance so that the
horizontal length of wire is in between the two magnets. Orient the wire
such that the horizontal length of wire is perpendicular to the
magnetic field. Zero out the digital balance and then turn on the power
supply. Adjust the current to +4 amperes and note the reading on the
scale. In your Excel spreadsheet record the current and the effective mass
due to the magnetic force on the wire. Reduce the current in 0.5 amperes
steps until the current equals zero. Once the current is zero, swap the red
and black wires that go into the power supply. This will allow you to send
a current in the opposite direction in the wire. Now continue to decrease
the current by 0.5 ampere steps until the current is –4 amperes.
- Once you have done so,
turn off the power supply and return the black and red wires to their
original locations. Also remove the magnet-and-cup configuration from the
digital balance.
- Use your spreadsheet to
calculate FB from meg.
Both should be in newtons. Also use your spreadsheet to calculate IL
(in Ampere-meters), which is the magnetic force divided by the magnetic
field. Plot meg vs. IL. Add a trend line
(best-fit line) to the graph and add the equation to the chart. Use the
linest command in Excel (see page 67 for a refresher on Excel) and
report the slope and intercept to 90% confidence. What is the slope and
what is the intercept?
B. Validate the sin(θ) Dependence of the
Magnetic Force
- Place the magnet and cup
system on the digital balance and orient the digital balance so that the
horizontal length of wire is in between the two magnets. Orient the wire
such that the horizontal length of wire is parallel to the magnetic
field. This corresponds to an angle of zero degrees. Zero out the
digital balance and then turn on the power supply. Adjust the current to +4
amperes and note the reading on the scale. In your Excel spreadsheet record
the angle and the effective mass due to the magnetic force on the wire.
Adjust the angle of the magnet so that the angle between the wire and the
magnetic field is now 30 degrees. Again note the reading on the scale for
this angle. Repeat for angular steps of 30 degrees until you get to 360
degrees noting the reading on the scale and angle.
- Use your spreadsheet to
calculate FB from meg.
Also use your spreadsheet to calculate I L |B| sin(θ). Plot
meg vs. I L |B| sin(θ). Note that
Excel expects angles to be in radians and hence you must use θ*PI()/180 for
the angle. Add a trend line (best-fit line) to the graph and add the
equation to the chart. Use the linest command in Excel and report the slope
and intercept to 90% confidence. What is the slope and what is the
intercept? What does this slope and intercept tell you? What would you
expect the slope and intercept to be for what is plotted?
- Use your spreadsheet to
plot meg vs. θ, where θ can be in degrees. What
is the shape of the graph?