Answers:1) angular acceleration is in the clockwise direction. 

 

Answers: Sim 1 does not have any angular acceleration but for Sim 2, the angular acceleration is in the positive direction

 

Answers: (1) positive

 

1. Into the screen (by the right hand rule)

 

Answers: 1. Since the magnitude of the angular velocity is increasing, the direction of the angular acceleration is the same as the direction of the angular velocity. According to the right hand rule, the direction of the angular acceleration is along the axis of rotation pointing into the plane of the computer screen in this animation.

 


 

(2) Inertia= E(mr^2). Both objects have the same mass and same R. Therefore, they both have the same moment of inertia. 

 

The pulleys have the same moment of inertia.

 

2-Since equal torques are acting on each pulley, the one with the least acceleration (sim 1) must have a larger I in order to offset the relatively small alpha. 

 

2. Since the mass in pulley #2 is distributed further from the axis of rotation, the moment of inertia is greater for pulley #2.

 

2)pulley one has a greater moment of inertia because it is harder to turn. 

 

2. Because both pulleys have the same mass and radius, they both experience the same torque, and therefore I1a1 = I2a2. Because a2 > a1 (because the mass on pulley 2 has a greater tangential velocity, therefore a greater angular velocity, and therefore a greater angular acceleration), the moment of inertia of the first pulley is greater than the moment of inertia of the second pulley (I1 > I2).


 

3. The magnitude of the torque T = rFsin(Theta), and because the radius of both pulleys are equal, the force on both pulleys are equal (force due to gravity on same mass odjects), and the angles (theta) are equal, the torques on both pulleys must be equal.

 

3. The torque is also greater for pulley #2.

 

 (3) Torque applied to the pulley is the same for both.

3. The torque applied to the pulley is greatest for the second pulley (the one whose mass that falls to the ground) because T = rFsin(theta) and, as a fore mentioned, the r and theta are the same for both pulleys and the force applied is greater on the second pulley.

3)pulley one has the greater torque because it has the larger tension.

 3-in both cases, the torque is equal. Why? because the moment arm is equal in both cases, as is the applied force and the angle of force application.